one consumer from the survey is selected at random. use reduced fractions for your responses to each of the…

one consumer from the survey is selected at random. use reduced fractions for your responses to each of the following questions.\nwhat is the probability that the consumer is 18 - 24 years of age, given that he/she dislikes crunchicles?\nwhat is the probability that the selected consumer dislikes crunchicles?\nwhat is the probability that the selected consumer is 35 - 55 years old or likes crunchicles?
Answer
Explanation:
Step1: Recall conditional - probability formula
The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. For the first question, let $A$ be the event that the consumer is 18 - 24 years old and $B$ be the event that the consumer dislikes Crunchicles. $P(A\cap B)=\frac{21}{300}$ and $P(B)=\frac{63}{300}$. Then $P(A|B)=\frac{\frac{21}{300}}{\frac{63}{300}}=\frac{21}{63}=\frac{1}{3}$.
Step2: Calculate probability of disliking Crunchicles
The probability that a selected consumer dislikes Crunchicles is $P=\frac{\text{Number of consumers who dislike Crunchicles}}{\text{Total number of consumers}}=\frac{63}{300}=\frac{21}{100}$.
Step3: Use the addition - rule of probability
The addition - rule of probability is $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event that the consumer is 35 - 55 years old and $B$ be the event that the consumer likes Crunchicles. $P(A)=\frac{93}{300}$, $P(B)=\frac{61}{300}$, and $P(A\cap B)=\frac{19}{300}$. Then $P(A\cup B)=\frac{93 + 61-19}{300}=\frac{135}{300}=\frac{9}{20}$.
Answer:
$\frac{1}{3}$ $\frac{21}{100}$ $\frac{9}{20}$