the owner of a bookstore plans to offer free childrens activities to get more customers in the door. he…

the owner of a bookstore plans to offer free childrens activities to get more customers in the door. he asked some visitors which activity they would prefer. this table shows the votes by age.\n| |craft hour|story hour|total|\n|--|--|--|--|\n|children|33|19|52|\n|adults|28|46|74|\n|total|61|65|126|\nbased on the survey, there appears to be an association between age and activity preference. complete the paragraph to describe this association.\nthe percentage of all visitors who voted for a craft hour is. among children, voted for a craft hour. so, a child would be likely to vote for a craft hour than a visitor chosen at random.

the owner of a bookstore plans to offer free childrens activities to get more customers in the door. he asked some visitors which activity they would prefer. this table shows the votes by age.\n| |craft hour|story hour|total|\n|--|--|--|--|\n|children|33|19|52|\n|adults|28|46|74|\n|total|61|65|126|\nbased on the survey, there appears to be an association between age and activity preference. complete the paragraph to describe this association.\nthe percentage of all visitors who voted for a craft hour is. among children, voted for a craft hour. so, a child would be likely to vote for a craft hour than a visitor chosen at random.

Answer

Explanation:

Step1: Calculate percentage of all visitors for craft hour

The number of visitors who voted for craft hour is 61, and the total number of visitors is 126. The percentage is $\frac{61}{126}\times100%\approx48.4%$.

Step2: Calculate percentage of children for craft hour

Among children, 33 voted for craft hour out of 52 children. The percentage is $\frac{33}{52}\times100%\approx63.5%$.

Step3: Compare the percentages

Since $63.5%>48.4%$, a child is more likely to vote for a craft - hour than a visitor chosen at random.

Answer:

The percentage of all visitors who voted for a craft hour is approximately $48.4%$. Among children, approximately $63.5%$ voted for a craft hour. So, a child would be more likely to vote for a craft hour than a visitor chosen at random.