as part of a fundraising activity, twenty - four girl scouts sold boxes of cookies in their community. the…

as part of a fundraising activity, twenty - four girl scouts sold boxes of cookies in their community. the data shows the number of boxes sold by each girl scout as follows: 9, 10, 30, 10, 10, 15, 15, 8, 9, 24, 24, 30, 30, 9, 24, 24, 26, 28, 30, 15, 16, 20, 24, 24. the council wants to represent the data using a box plot. use the geogebra calculator spreadsheet to input the data and generate a boxplot. use the keypad to enter your answer in the box. more symbols can be found using the drop - down arrow at the top of the keypad. parts of the boxplot value end of left whisker vertical line inside the box left edge of the box right edge of the box end of right whisker

as part of a fundraising activity, twenty - four girl scouts sold boxes of cookies in their community. the data shows the number of boxes sold by each girl scout as follows: 9, 10, 30, 10, 10, 15, 15, 8, 9, 24, 24, 30, 30, 9, 24, 24, 26, 28, 30, 15, 16, 20, 24, 24. the council wants to represent the data using a box plot. use the geogebra calculator spreadsheet to input the data and generate a boxplot. use the keypad to enter your answer in the box. more symbols can be found using the drop - down arrow at the top of the keypad. parts of the boxplot value end of left whisker vertical line inside the box left edge of the box right edge of the box end of right whisker

Answer

Answer:

  1. end of left whisker: 8
  2. vertical line inside the box: 24
  3. left edge of the box: 15
  4. right edge of the box: 26
  5. end of right whisker: 30

Explanation:

Step1: Order the data

8, 9, 9, 10, 10, 10, 15, 15, 16, 20, 24, 24, 24, 24, 24, 24, 26, 28, 30, 30, 30

Step2: Find the minimum

The minimum value is 8, which is the end of the left - whisker.

Step3: Find the first quartile ($Q_1$)

There are $n = 24$ data points. The position of $Q_1$ is $\frac{n + 1}{4}=6.25$. The 6th value is 10 and the 7th value is 15. $Q_1=15$.

Step4: Find the median

The position of the median for $n = 24$ is $\frac{n}{2}=12$ and $\frac{n}{2}+1 = 13$. The average of the 12th and 13th values (both 24) is 24, which is the vertical line inside the box.

Step5: Find the third quartile ($Q_3$)

The position of $Q_3$ is $\frac{3(n + 1)}{4}=18.75$. The 18th value is 26 and the 19th value is 28. $Q_3 = 26$.

Step6: Find the maximum

The maximum value is 30, which is the end of the right - whisker.