in a particular hospital, 6 newborn babies were delivered yesterday. here are their weights (in ounces)…

Explanation:

Step1: Calculate the mean

The mean $\mu$ of a population is $\mu=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. $n = 6$, $x_1=129$, $x_2 = 125$, $x_3=115$, $x_4 = 93$, $x_5=100$, $x_6=128$. $\sum_{i=1}^{6}x_{i}=129 + 125+115+93+100+128=690$. $\mu=\frac{690}{6}=115$.

Step2: Calculate the squared differences

$(x_1-\mu)^2=(129 - 115)^2=14^2 = 196$; $(x_2-\mu)^2=(125 - 115)^2=10^2 = 100$; $(x_3-\mu)^2=(115 - 115)^2=0^2 = 0$; $(x_4-\mu)^2=(93 - 115)^2=(-22)^2 = 484$; $(x_5-\mu)^2=(100 - 115)^2=(-15)^2 = 225$; $(x_6-\mu)^2=(128 - 115)^2=13^2 = 169$.

Step3: Calculate the variance

The population variance $\sigma^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\mu)^2}{n}$. $\sum_{i = 1}^{6}(x_{i}-\mu)^2=196 + 100+0+484+225+169 = 1174$. $\sigma^{2}=\frac{1174}{6}\approx195.67$.

Step4: Calculate the standard deviation

The population standard deviation $\sigma=\sqrt{\sigma^{2}}$. $\sigma=\sqrt{195.67}\approx13.99$.

Answer:

$13.99$