people at the state fair were surveyed about which type of lemonade they preferred. the results are shown…

people at the state fair were surveyed about which type of lemonade they preferred. the results are shown below. pink lemonade: 156 males, 72 females yellow lemonade: 104 males, 48 females the events \prefers pink lemonade\ and \female\ are independent because o p(pink lemonade | female) = p(pink lemonade) = 0.6. o p(female | pink lemonade ) = p(pink lemonade) = 0.3. o p(pink lemonade | female) = 0.3 and p(pink lemonade) = 0.6. o p(female | pink lemonade ) = 0.3 and p(pink lemonade) = 0.6.

people at the state fair were surveyed about which type of lemonade they preferred. the results are shown below. pink lemonade: 156 males, 72 females yellow lemonade: 104 males, 48 females the events \prefers pink lemonade\ and \female\ are independent because o p(pink lemonade | female) = p(pink lemonade) = 0.6. o p(female | pink lemonade ) = p(pink lemonade) = 0.3. o p(pink lemonade | female) = 0.3 and p(pink lemonade) = 0.6. o p(female | pink lemonade ) = 0.3 and p(pink lemonade) = 0.6.

Answer

Explanation:

Step1: Calculate total number of people

Total number of people = 156 + 72+104 + 48=380.

Step2: Calculate (P(\text{pink lemonade}))

Number of people who prefer pink lemonade = 156 + 72 = 228. So (P(\text{pink lemonade})=\frac{228}{380}=0.6).

Step3: Calculate number of females

Number of females = 72 + 48 = 120.

Step4: Calculate (P(\text{pink lemonade}|\text{female}))

Using the formula (P(A|B)=\frac{P(A\cap B)}{P(B)}), (P(\text{pink lemonade}\cap\text{female})=\frac{72}{380}), (P(\text{female})=\frac{120}{380}), then (P(\text{pink lemonade}|\text{female})=\frac{\frac{72}{380}}{\frac{120}{380}}=\frac{72}{120}=0.6).

Step5: Check independence

Two events (A) and (B) are independent if (P(A|B)=P(A)). Here (A) is the event of preferring pink - lemonade and (B) is the event of being female. Since (P(\text{pink lemonade}|\text{female}) = P(\text{pink lemonade})=0.6), the events are independent.

Answer:

(P(\text{pink lemonade}|\text{female}) = P(\text{pink lemonade}) = 0.6)