every person has blood type o, a, b, or ab. a random group of people are blood - typed, and the results are…

every person has blood type o, a, b, or ab. a random group of people are blood - typed, and the results are shown in the table.\n\n| blood type | number of people |\n| ---- | ---- |\n| o | 22 |\n| a | 20 |\n| b | 6 |\n| ab | 2 |\n\nuse the table to determine the following probabilities\nthe probability that a randomly chosen person from this group has type b is \nthe probability that a randomly chosen person from this group has type ab is \nthe probability that a randomly chosen person from this group has type b or type ab blood is

every person has blood type o, a, b, or ab. a random group of people are blood - typed, and the results are shown in the table.\n\n| blood type | number of people |\n| ---- | ---- |\n| o | 22 |\n| a | 20 |\n| b | 6 |\n| ab | 2 |\n\nuse the table to determine the following probabilities\nthe probability that a randomly chosen person from this group has type b is \nthe probability that a randomly chosen person from this group has type ab is \nthe probability that a randomly chosen person from this group has type b or type ab blood is

Answer

Explanation:

Step1: Calculate total number of people

$22 + 20+6 + 2=50$

Step2: Calculate probability of type B

The number of people with type B is 6. Probability $P(B)=\frac{6}{50}=\frac{3}{25}$

Step3: Calculate probability of type AB

The number of people with type AB is 2. Probability $P(AB)=\frac{2}{50}=\frac{1}{25}$

Step4: Calculate probability of type B or type AB

Using the formula $P(B\cup AB)=P(B)+P(AB)$. Since $P(B)=\frac{6}{50}$ and $P(AB)=\frac{2}{50}$, then $P(B\cup AB)=\frac{6 + 2}{50}=\frac{8}{50}=\frac{4}{25}$

Answer:

The probability that a randomly - chosen person from this group has type B is $\frac{3}{25}$ The probability that a randomly - chosen person from this group has type AB is $\frac{1}{25}$ The probability that a randomly - chosen person from this group has type B or type AB blood is $\frac{4}{25}$