a player in a board game will roll two standard dice. she needs to roll a 9, 10, or 11 to win the game…

a player in a board game will roll two standard dice. she needs to roll a 9, 10, or 11 to win the game. since the sample space consists of a total of ways two dice can come up, there is a chance that the player will roll a 9, 10, or 11 and win the game. response 1: 36, 21, 25, 12 response 2: 36%, 21%, 25%, 15%
Answer
Explanation:
Step1: Calculate total outcomes
Each die has 6 faces. When rolling two dice, the total number of outcomes in the sample - space is $6\times6 = 36$ (by the multiplication principle).
Step2: Calculate favorable outcomes
From the table, the number of ways to roll a 9 is 4, a 10 is 3, and an 11 is 2. So the number of favorable outcomes is $4 + 3+2=9$.
Step3: Calculate probability
The probability $P$ of an event is the number of favorable outcomes divided by the number of total outcomes. So $P=\frac{9}{36}=0.25 = 25%$.
Answer:
Response 1: 36 Response 2: 25%