4 a popular board game includes a five - section spinner to determine the number of spaces a player moves…

4 a popular board game includes a five - section spinner to determine the number of spaces a player moves during a turn. the results of 10 spins are shown. spin 1 2 3 4 5 6 7 8 9 10 spaces moved 5 4 2 5 1 3 5 4 5 2 what is the experimental probability a player will move 2 spaces and 5 spaces during a game? a 0.1 c 0.08 b 0.6 d not here
Answer
Explanation:
Step1: Count occurrences
Count the number of times 2 and 5 appear. 2 appears 2 times and 5 appears 4 times. So in total, the favorable - outcomes (moving 2 or 5 spaces) occur $2 + 4=6$ times.
Step2: Calculate experimental probability
The experimental probability $P$ is the number of favorable outcomes divided by the total number of outcomes. The total number of spins is $n = 10$. So $P=\frac{6}{10}=0.6$.
Answer:
B. 0.6