the probability of a detasseler making less than $13/hr is given by p(z < 0.5) ≈ %.
the probability of a detasseler making less than $13/hr is given by p(z < 0.5) ≈ %.
Answer
Answer:
69.15
Explanation:
Step1: Use z - table
We refer to the standard normal distribution z - table.
Step2: Find the value
The value corresponding to $z = 0.5$ in the z - table is 0.6915. Since $P(z<0.5)$ represents a probability, as a percentage it is $0.6915\times100 = 69.15%$.