the probability that the dog bites the mailman is 0.21. find the probability that the dog does not bite the…

the probability that the dog bites the mailman is 0.21. find the probability that the dog does not bite the mailman.

the probability that the dog bites the mailman is 0.21. find the probability that the dog does not bite the mailman.

Answer

Explanation:

Step1: Recall probability rule

The sum of the probability of an event happening and not - happening is 1. Let $P(A)$ be the probability of the dog biting the mailman and $P(\overline{A})$ be the probability of the dog not biting the mailman. So $P(A)+P(\overline{A}) = 1$.

Step2: Solve for $P(\overline{A})$

We know that $P(A)=0.21$. Then $P(\overline{A})=1 - P(A)$. Substitute $P(A) = 0.21$ into the formula: $P(\overline{A})=1 - 0.21$. $P(\overline{A})=0.79$

Answer:

$0.79$