what is the probability that either event a or event b will occur?\np(a) = \\frac{13}{19}\np(b) =…

what is the probability that either event a or event b will occur?\np(a) = \\frac{13}{19}\np(b) = \\frac{12}{19}\np(a and b) = \\frac{10}{19}\np(a or b) = p(a) + p(b) - p(a and b)\np(a or b) = \\frac{?}{19}

what is the probability that either event a or event b will occur?\np(a) = \\frac{13}{19}\np(b) = \\frac{12}{19}\np(a and b) = \\frac{10}{19}\np(a or b) = p(a) + p(b) - p(a and b)\np(a or b) = \\frac{?}{19}

Answer

Explanation:

Step1: Substitute the given values

We know that $P(A)=\frac{13}{19}$, $P(B)=\frac{12}{19}$ and $P(A\ and\ B)=\frac{10}{19}$. Using the formula $P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$. $P(A\ or\ B)=\frac{13}{19}+\frac{12}{19}-\frac{10}{19}$

Step2: Calculate the numerator

Add the first two - fraction numerators and then subtract the third - fraction numerator. $(13 + 12-10)$. $13+12 - 10=15$ So $P(A\ or\ B)=\frac{15}{19}$

Answer:

$\frac{15}{19}$