is the probability of getting a number greater than 2 on throwing a die once.

Explanation:

Step1: Determine total outcomes

A die has 6 faces numbered 1 - 6. So total outcomes $n(S)=6$.

Step2: Determine favorable outcomes

Numbers greater than 2 on a die are 3, 4, 5, 6. So favorable outcomes $n(A) = 4$.

Step3: Calculate probability

The probability formula is $P(A)=\frac{n(A)}{n(S)}$. Substituting values, we get $P(A)=\frac{4}{6}=\frac{2}{3}$.

Answer:

$\frac{2}{3}$