the probability of a new york teenager owning a skateboard is 0.37, of owning a bicycle is 0.81 and of…

the probability of a new york teenager owning a skateboard is 0.37, of owning a bicycle is 0.81 and of owning both is 0.36. if a new york teenager is chosen at random, what is the probability that the teenager owns a skateboard or a bicycle?\n1.18\n0.7\n0.82\nnone of the above

the probability of a new york teenager owning a skateboard is 0.37, of owning a bicycle is 0.81 and of owning both is 0.36. if a new york teenager is chosen at random, what is the probability that the teenager owns a skateboard or a bicycle?\n1.18\n0.7\n0.82\nnone of the above

Answer

Explanation:

Step1: Recall probability formula

Use the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event of owning a skate - board and $B$ be the event of owning a bicycle.

Step2: Substitute given values

We know that $P(A) = 0.37$, $P(B)=0.81$ and $P(A\cap B)=0.36$. Then $P(A\cup B)=0.37 + 0.81-0.36$.

Step3: Calculate result

$P(A\cup B)=0.82$.

Answer:

C. 0.82