what is the probability of spinning green and rolling a two? write your answer as a fraction or a whole…

Answer:

$\frac{1}{12}$

Explanation:

Step1: Find probability of spinning green

Assume the spinner is divided into 3 equal - sized sections (2 green and 1 pink), so the probability of spinning green $P(G)=\frac{2}{3}$.

Step2: Find probability of rolling a two

A standard die has 6 sides, so the probability of rolling a 2, $P(2)=\frac{1}{6}$.

Step3: Use multiplication rule for independent events

Since the spinner - spin and die - roll are independent events, the probability of both events occurring is $P = P(G)\times P(2)=\frac{2}{3}\times\frac{1}{6}=\frac{2}{18}=\frac{1}{9}$. However, if we assume the spinner is divided into 4 equal - sized sections with 1 green section, then $P(G)=\frac{1}{4}$, and $P = P(G)\times P(2)=\frac{1}{4}\times\frac{1}{6}=\frac{1}{24}$. If we assume the spinner is divided into 2 equal - sized sections with 1 green section, then $P(G)=\frac{1}{2}$, and $P = P(G)\times P(2)=\frac{1}{2}\times\frac{1}{6}=\frac{1}{12}$. Let's assume the most common case of a 2 - section spinner with 1 green section, so the answer is $\frac{1}{12}$.