what is the probability of tossing a coin and getting a head 4 times in a row?\na. $\frac{1}{2}$\nb…

what is the probability of tossing a coin and getting a head 4 times in a row?\na. $\frac{1}{2}$\nb. $\frac{1}{4}$\nc. $\frac{1}{8}$\nd. $\frac{1}{16}$\ne. $\frac{1}{24}$

what is the probability of tossing a coin and getting a head 4 times in a row?\na. $\frac{1}{2}$\nb. $\frac{1}{4}$\nc. $\frac{1}{8}$\nd. $\frac{1}{16}$\ne. $\frac{1}{24}$

Answer

Explanation:

Step1: Determine single - toss probability

The probability of getting a head in a single coin - toss is $P(H)=\frac{1}{2}$.

Step2: Use multiplication rule for independent events

Since coin - tosses are independent events, the probability of getting 4 heads in a row is $P = \frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}$.

Step3: Calculate the result

$P=\frac{1}{16}$.

Answer:

D. $\frac{1}{16}$