a probability value is listed at the top of each column. determine the probability for each situation, then…

Explanation:

Step1: Recall probability formula

$P(A)=\frac{n(A)}{n(S)}$, where $n(A)$ is the number of favorable outcomes and $n(S)$ is the total number of outcomes.

Step2: Probability of choosing a soccer - ball

$n(S)=4 + 1+3=8$, $n(A) = 4$, $P=\frac{4}{8}=0.5$.

Step3: Probability of choosing a blue marble

$n(S)=3 + 1+4 + 2=10$, $n(A)=4$, $P=\frac{4}{10}=0.4$.

Step4: Probability of rolling an even number on a die

A die has 6 sides, even numbers are 2, 4, 6. So $n(S)=6$, $n(A)=3$, $P=\frac{3}{6}=0.5$.

Step5: Probability of flipping a head on a fair coin

$n(S)=2$, $n(A)=1$, $P=\frac{1}{2}=0.5$.

Step6: Probability of choosing a red block

$n(S)=1 + 1+3=5$, $n(A)=1$, $P=\frac{1}{5}=0.2$.

Step7: Probability of choosing a tennis ball

$n(S)=5 + 3+6 + 1=15$, $n(A)=3$, $P=\frac{3}{15}=0.2$.

Answer:

• 0.5: The probability of choosing a soccer ball out of a bag containing 4 soccer balls, 1 playground ball, and 3 basketballs; The probability of rolling an even number on a die; The probability of flipping a head on a fair coin.
• 0.2: The probability of choosing a red block out of a bag containing 1 red, 1 blue, and 3 green blocks; The probability of choosing a tennis ball out of a bag containing 5 rubber balls, 3 tennis balls, 6 bouncy balls, and 1 squishy ball.
• 0.4: The probability of choosing a blue marble out of a bag containing 3 red, 1 green, 4 blue and 2 yellow marbles.