question 3 of 14 (1 point) bowl winner scores the data show the scores of the winning teams of a certain…

question 3 of 14 (1 point) bowl winner scores the data show the scores of the winning teams of a certain annual foot and standard deviation for the data. 24 49 47 31 47 47 30 25 40 46 37 36 32 27 19 39 34 48 18 37 send data to excel part 1 of 2 find the range. the range is 31. part: 1 / 2 part 2 of 2 find the variance and the standard deviation. assume the data represent samples, and use the variance and standard deviation. round your answers to at least one decimal place. the variance is. the standard deviation is.

question 3 of 14 (1 point) bowl winner scores the data show the scores of the winning teams of a certain annual foot and standard deviation for the data. 24 49 47 31 47 47 30 25 40 46 37 36 32 27 19 39 34 48 18 37 send data to excel part 1 of 2 find the range. the range is 31. part: 1 / 2 part 2 of 2 find the variance and the standard deviation. assume the data represent samples, and use the variance and standard deviation. round your answers to at least one decimal place. the variance is. the standard deviation is.

Answer

Explanation:

Step1: Calculate the mean

Let the data set be (x_1,x_2,\cdots,x_n). First, find the sum of the data values. (n = 20). (\sum_{i = 1}^{20}x_i=24 + 49+47+31+47+47+30+25+40+46+37+36+32+27+19+39+34+48+18+37=710) The mean (\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}=\frac{710}{20}=35.5)

Step2: Calculate the squared - differences

For each data value (x_i), calculate ((x_i-\bar{x})^2). For example, when (x_1 = 24), ((24 - 35.5)^2=(- 11.5)^2 = 132.25). Do this for all 20 data values and sum them up. (\sum_{i = 1}^{20}(x_i - 35.5)^2=132.25+182.25+132.25+19.53+132.25+132.25+30.25+110.25+20.25+110.25+2.25+0.25+10.25+72.25+272.25+12.25+2.25+156.25+290.25+2.25 = 1599)

Step3: Calculate the variance

Since we assume the data is a sample, the variance (s^2=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})^2}{n - 1}). Here, (n=20), so (s^2=\frac{1599}{19}\approx84.2)

Step4: Calculate the standard deviation

The standard deviation (s=\sqrt{s^2}), so (s=\sqrt{84.2}\approx9.2)

Answer:

The variance is (84.2) The standard deviation is (9.2)