question 1 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the…

question 1 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the probability of intersection is 29%. a student is selected at random and questioned about their technology usage. what is the probability of the student using at least 1 of the two devices? 77% 34% 29% 72%

question 1 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the probability of intersection is 29%. a student is selected at random and questioned about their technology usage. what is the probability of the student using at least 1 of the two devices? 77% 34% 29% 72%

Answer

Explanation:

Step1: Recall the formula for the probability of the union

Let (A) be the event of using i - phones ((P(A)=0.72)) and (B) be the event of using Mac - Books ((P(B) = 0.34)), and (P(A\cap B)=0.29). The formula for (P(A\cup B)) is (P(A\cup B)=P(A)+P(B)-P(A\cap B)).

Step2: Substitute the values into the formula

Substitute (P(A) = 0.72), (P(B)=0.34) and (P(A\cap B)=0.29) into the formula: (P(A\cup B)=0.72 + 0.34-0.29).

Step3: Calculate the result

(0.72+0.34 - 0.29=0.77).

Answer:

77%