question 2 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the…

question 2 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the probability of intersection is 29%. a student is selected at random and questioned about their technology usage. what is the probability of the student using neither device? 0 77% 0 72% 0 29% 0 23% 1 points save answer

question 2 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the probability of intersection is 29%. a student is selected at random and questioned about their technology usage. what is the probability of the student using neither device? 0 77% 0 72% 0 29% 0 23% 1 points save answer

Answer

Explanation:

Step1: Use the principle of inclusion - exclusion

Let (A) be the set of students using Mac - Books and (B) be the set of students using iPhones. The formula for (P(A\cup B)) is (P(A\cup B)=P(A)+P(B)-P(A\cap B)). Given (P(A) = 0.34), (P(B)=0.72) and (P(A\cap B)=0.29). [P(A\cup B)=0.34 + 0.72-0.29]

Step2: Calculate (P(A\cup B))

[P(A\cup B)=0.77]

Step3: Calculate the probability of using neither

The probability of using neither is (1 - P(A\cup B)). [1 - 0.77=0.23]

Answer:

0.23 or 23%