question #3\njoey plans to survey his classmates about which presidential candidate for whom they will vote…

question #3\njoey plans to survey his classmates about which presidential candidate for whom they will vote. which group(s) of classmates should joey poll for valid results.\nselect all that apply.\na randomly selected classmates of both genders\nb randomly selected classmates in the environmental club\nc randomly selected females in his class\nd randomly selected classmates from each homeroom\n\nquestion #4\nvictoria compares her math test scores to her science test scores. use the data to answer question.\n| math scores | science scores |\n| ---- | ---- |\n| 88 | 92 |\n| 72 | 85 |\n| 94 | 95 |\n| 86 | 53 |\n| 95 | 90 |\nwhat is the mean absolute deviation of victorias science scores?\na 83\nb 60\nc 12\nd 10

question #3\njoey plans to survey his classmates about which presidential candidate for whom they will vote. which group(s) of classmates should joey poll for valid results.\nselect all that apply.\na randomly selected classmates of both genders\nb randomly selected classmates in the environmental club\nc randomly selected females in his class\nd randomly selected classmates from each homeroom\n\nquestion #4\nvictoria compares her math test scores to her science test scores. use the data to answer question.\n| math scores | science scores |\n| ---- | ---- |\n| 88 | 92 |\n| 72 | 85 |\n| 94 | 95 |\n| 86 | 53 |\n| 95 | 90 |\nwhat is the mean absolute deviation of victorias science scores?\na 83\nb 60\nc 12\nd 10

Answer

Question #3

Brief Explanations:

For a valid survey about presidential - candidate voting preferences among classmates, the sample should be representative of the entire class population. Randomly selecting classmates of both genders (A) and randomly selected classmates from each homeroom (D) help ensure a diverse and representative sample. Selecting only from the Environmental Club (B) may introduce bias as club members may have similar political views, and selecting only females (C) is not representative of the whole class.

Answer:

A. randomly selected classmates of both genders, D. randomly selected classmates from each homeroom

Question #4

Explanation:

Step1: Calculate the mean of science scores

The science scores are 92, 85, 95, 53, 90. The mean $\bar{x}=\frac{92 + 85+95+53+90}{5}=\frac{415}{5}=83$.

Step2: Calculate the absolute deviations

$|92 - 83|=9$, $|85 - 83| = 2$, $|95 - 83|=12$, $|53 - 83|=30$, $|90 - 83| = 7$.

Step3: Calculate the mean of the absolute deviations

The mean absolute deviation $MAD=\frac{9 + 2+12+30+7}{5}=\frac{60}{5}=12$.

Answer:

C. 12