question 5\ne and f are mutually exclusive events. p(e) = 0.91; p(f) = 0.42. find p(e | f)

Explanation:

Step1: Recall the definition of mutually - exclusive events

If E and F are mutually exclusive events, then (P(E\cap F)=0).

Step2: Recall the formula for conditional probability

The formula for conditional probability is (P(E|F)=\frac{P(E\cap F)}{P(F)}).

Step3: Substitute the value of (P(E\cap F)) into the conditional - probability formula

Since (P(E\cap F) = 0) (because E and F are mutually exclusive) and (P(F)=0.42), then (P(E|F)=\frac{0}{0.42}=0).

Answer:

0