question 1\n1 pts\na standardized variable has mean \n\nand standard deviation \n\n. (enter numerical values…

question 1\n1 pts\na standardized variable has mean \n\nand standard deviation \n\n. (enter numerical values for each blank.)

question 1\n1 pts\na standardized variable has mean \n\nand standard deviation \n\n. (enter numerical values for each blank.)

Answer

Explanation:

Step1: Recall standardization formula

The formula for standardizing a variable $X$ is $Z=\frac{X - \mu}{\sigma}$, where $\mu$ is the mean of $X$ and $\sigma$ is the standard - deviation of $X$. When $X$ is standardized to $Z$, the mean of $Z$ is calculated as $E(Z)=E(\frac{X - \mu}{\sigma})=\frac{E(X)-\mu}{\sigma}=\frac{\mu - \mu}{\sigma}=0$.

Step2: Recall standard - deviation of standardized variable

The standard - deviation of $Z$ is $SD(Z)=\sqrt{Var(Z)}$. Since $Var(Z)=Var(\frac{X - \mu}{\sigma})=\frac{1}{\sigma^{2}}Var(X)=\frac{\sigma^{2}}{\sigma^{2}} = 1$, then $SD(Z) = 1$.

Answer:

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