question 1\n1 pts\na standardized variable has mean \n\nand standard deviation \n\n. (enter numerical values…

question 1\n1 pts\na standardized variable has mean \n\nand standard deviation \n\n. (enter numerical values for each blank.)
Answer
Explanation:
Step1: Recall standardization formula
The formula for standardizing a variable $X$ is $Z=\frac{X - \mu}{\sigma}$, where $\mu$ is the mean of $X$ and $\sigma$ is the standard - deviation of $X$. When $X$ is standardized to $Z$, the mean of $Z$ is calculated as $E(Z)=E(\frac{X - \mu}{\sigma})=\frac{E(X)-\mu}{\sigma}=\frac{\mu - \mu}{\sigma}=0$.
Step2: Recall standard - deviation of standardized variable
The standard - deviation of $Z$ is $SD(Z)=\sqrt{Var(Z)}$. Since $Var(Z)=Var(\frac{X - \mu}{\sigma})=\frac{1}{\sigma^{2}}Var(X)=\frac{\sigma^{2}}{\sigma^{2}} = 1$, then $SD(Z) = 1$.
Answer:
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