question a random sample of students was surveyed and asked to list their grade level and whether or not…

question a random sample of students was surveyed and asked to list their grade level and whether or not they have a pet. results are shown in the table below. pets survey \n| | pets | no pets |\n| ---- | ---- | ---- |\n| 6th grade | 20 | 26 |\n| 7th grade | 30 | 16 |\n| 8th grade | 26 | 27 | what percent of the 6th - graders have a pet? round your answer to the nearest tenth of a percent.

question a random sample of students was surveyed and asked to list their grade level and whether or not they have a pet. results are shown in the table below. pets survey \n| | pets | no pets |\n| ---- | ---- | ---- |\n| 6th grade | 20 | 26 |\n| 7th grade | 30 | 16 |\n| 8th grade | 26 | 27 | what percent of the 6th - graders have a pet? round your answer to the nearest tenth of a percent.

Answer

Explanation:

Step1: Find total 6th - graders

Add the number of 6th - graders with pets and without pets. $20 + 26=46$.

Step2: Calculate the percentage of 6th - graders with pets

Use the formula $\text{Percentage}=\frac{\text{Number of 6th - graders with pets}}{\text{Total number of 6th - graders}}\times100%$. So, $\frac{20}{46}\times 100%$. $\frac{20}{46}\times100%=\frac{2000}{46}% \approx 43.5%$.

Answer:

$43.5$