question\nthere is a spinner with 13 equal areas, numbered 1 through 13. if the spinner is spun one time…

question\nthere is a spinner with 13 equal areas, numbered 1 through 13. if the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?

question\nthere is a spinner with 13 equal areas, numbered 1 through 13. if the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?

Answer

Explanation:

Step1: Find common multiples

Find the numbers from 1 - 13 that are multiples of both 2 and 3. Multiples of 2 are 2, 4, 6, 8, 10, 12. Multiples of 3 are 3, 6, 9, 12. The common multiples are 6 and 12. So there are 2 such numbers.

Step2: Calculate probability

The probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Here, the total number of outcomes is 13 (since there are 13 equal - areas on the spinner), and the number of favorable outcomes is 2. So $P=\frac{2}{13}$.

Answer:

$\frac{2}{13}$