this question has two parts. use the information to answer part a and part b.\nlet e be the event that tom…

this question has two parts. use the information to answer part a and part b.\nlet e be the event that tom has english homework, and let h be the event that tom has history homework.\np(e)=0.6\np(h)=0.4\np(e and h)=0.3\npart a\nare e and h dependent or independent events?\na. dependent\nb. independent\npart b\nwhich equation justifies why the events are dependent or independent?\na. p(e and h)≠p(e)+p(h)\nb. p(e and h)≠p(e)×p(h)\nc. p(e and h)=p(e)-p(h)\nd. p(e and h)=p(e)×p(h)

this question has two parts. use the information to answer part a and part b.\nlet e be the event that tom has english homework, and let h be the event that tom has history homework.\np(e)=0.6\np(h)=0.4\np(e and h)=0.3\npart a\nare e and h dependent or independent events?\na. dependent\nb. independent\npart b\nwhich equation justifies why the events are dependent or independent?\na. p(e and h)≠p(e)+p(h)\nb. p(e and h)≠p(e)×p(h)\nc. p(e and h)=p(e)-p(h)\nd. p(e and h)=p(e)×p(h)

Answer

Explanation:

Step1: Recall independence - formula

For two events (E) and (H) to be independent, (P(E\cap H)=P(E)\times P(H)). Calculate (P(E)\times P(H)): [P(E)\times P(H)=0.6\times0.4 = 0.24]

Step2: Compare with (P(E\cap H))

Given (P(E\cap H) = 0.3). Since (0.3\neq0.24), i.e., (P(E\cap H)\neq P(E)\times P(H)), the events are dependent.

Answer:

Part A: A. dependent Part B: B. (P(E\text{ and }H)\neq P(E)\times P(H))