a radio disc jockey has 8 songs on this upcoming hours playlist: 2 are rock songs, 3 are reggae songs, and 3…

a radio disc jockey has 8 songs on this upcoming hours playlist: 2 are rock songs, 3 are reggae songs, and 3 are country songs. the disc jockey randomly chooses the first song to play, and then she randomly chooses the second song from the remaining ones. what is the probability that both songs are reggae songs? write your answer as a fraction in simplest form.

a radio disc jockey has 8 songs on this upcoming hours playlist: 2 are rock songs, 3 are reggae songs, and 3 are country songs. the disc jockey randomly chooses the first song to play, and then she randomly chooses the second song from the remaining ones. what is the probability that both songs are reggae songs? write your answer as a fraction in simplest form.

Answer

Explanation:

Step1: Calculate first - song probability

The probability of choosing a reggae song as the first song is the number of reggae songs divided by the total number of songs. There are 3 reggae songs and 8 total songs, so the probability $P_1=\frac{3}{8}$.

Step2: Calculate second - song probability

After choosing one reggae song as the first song, there are 2 reggae songs left and 7 total songs left. So the probability of choosing a reggae song as the second song given that the first song was reggae is $P_2 = \frac{2}{7}$.

Step3: Calculate joint probability

For dependent events, the probability of both events occurring is the product of their probabilities. So $P = P_1\times P_2=\frac{3}{8}\times\frac{2}{7}=\frac{3\times2}{8\times7}=\frac{6}{56}=\frac{3}{28}$.

Answer:

$\frac{3}{28}$