receives the newspaper at least one day per week?\nprobability distribution\n0.45\n0.4\n0.35\n0.3\n0.25\n0.2\…

receives the newspaper at least one day per week?\nprobability distribution\n0.45\n0.4\n0.35\n0.3\n0.25\n0.2\n0.15\n0.1\n0.05\n0\n0 days 1 day 2 days 3 days 4 days 5 days 6 days 7 days\nx\n16%\n33%\n41%\n83%

receives the newspaper at least one day per week?\nprobability distribution\n0.45\n0.4\n0.35\n0.3\n0.25\n0.2\n0.15\n0.1\n0.05\n0\n0 days 1 day 2 days 3 days 4 days 5 days 6 days 7 days\nx\n16%\n33%\n41%\n83%

Answer

Explanation:

Step1: Recall probability rule

The probability of receiving the newspaper at least one day per week is $P(X\geq1)$. We know that $P(X\geq1)=1 - P(X = 0)$.

Step2: Read $P(X = 0)$ from graph

From the probability - distribution graph, $P(X = 0)=0.17$.

Step3: Calculate $P(X\geq1)$

$P(X\geq1)=1 - 0.17=0.83$.

Answer:

83%