refer to the accompanying data display that results from a simple random sample of times (minutes) between…

refer to the accompanying data display that results from a simple random sample of times (minutes) between eruptions of the old faithful geyser. the confidence level of 95% was used. complete parts (a) and (b) below. tinterval (85.74,91.76) x = 88.75 sx = 8.897431411 n = 36 a. express the confidence interval in the format that uses the \less than\ symbol. round the confidence interval limits given that the original times are all rounded to one decimal place. 85.74 min < μ < 91.76 min (round to two decimal places as needed.) b. identify the best point estimate of μ and the margin of error. the point estimate of μ is minutes. (round to two decimal places as needed.)

refer to the accompanying data display that results from a simple random sample of times (minutes) between eruptions of the old faithful geyser. the confidence level of 95% was used. complete parts (a) and (b) below. tinterval (85.74,91.76) x = 88.75 sx = 8.897431411 n = 36 a. express the confidence interval in the format that uses the \less than\ symbol. round the confidence interval limits given that the original times are all rounded to one decimal place. 85.74 min < μ < 91.76 min (round to two decimal places as needed.) b. identify the best point estimate of μ and the margin of error. the point estimate of μ is minutes. (round to two decimal places as needed.)

Answer

Explanation:

Step1: Recall point - estimate formula

The best point - estimate of the population mean $\mu$ is the sample mean $\bar{x}$. Given $\bar{x}=88.75$.

Step2: Recall margin - of - error formula

The margin of error $E$ for a confidence interval $(L, U)$ (lower limit $L$ and upper limit $U$) is calculated as $E=\frac{U - L}{2}$. Here, $L = 85.74$ and $U=91.76$. So $E=\frac{91.76 - 85.74}{2}=\frac{6.02}{2}=3.01$.

Answer:

The point estimate of $\mu$ is $88.75$ minutes. The margin of error is $3.01$ minutes.