the relative frequency table shows the results of a survey in which parents were asked how much time their…

the relative frequency table shows the results of a survey in which parents were asked how much time their children spend playing outside and how much time they spend using electronics.\ntime spent by children\n| |at least 1 hr/day using electronics|less than 1 hr/day using electronics|total|\n|--|--|--|--|\n|at least 1 hr/day outside|2|14|16|\n|less than 1 hr/day outside|42|6|48|\n|total|44|20|64|\ngiven that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics?\n0.22\n0.25\n0.70\n0.88
Answer
Explanation:
Step1: Identify conditional probability formula
Conditional probability formula: ( P(A|B) = \frac{n(A \cap B)}{n(B)} )
Step2: Extract values from the table
For event ( B ) (at least 1 hr/day outside), total is 16. For ( A \cap B ) (less than 1 hr/day electronics and at least 1 hr/day outside), value is 14.
Step3: Calculate the probability
( P(A|B) = \frac{14}{16} = 0.875 )
Step4: Round to nearest hundredth
0.875 rounded to nearest hundredth is 0.88
Answer:
D. 0.88