the research department of a board game company surveyed some shoppers at a local mall. the team asked…

the research department of a board game company surveyed some shoppers at a local mall. the team asked shoppers how often they read the news, among other questions. then the team played a memory card game with the shoppers. they recorded how many cards each shopper remembered. 1 - 3 cards 4 - 6 cards 0 times a week 7 2 1 - 2 times a week 5 3 what is the probability that a randomly selected shopper remembered 1 - 3 cards given that the shopper reads the news 0 times a week? simplify any fractions.

the research department of a board game company surveyed some shoppers at a local mall. the team asked shoppers how often they read the news, among other questions. then the team played a memory card game with the shoppers. they recorded how many cards each shopper remembered. 1 - 3 cards 4 - 6 cards 0 times a week 7 2 1 - 2 times a week 5 3 what is the probability that a randomly selected shopper remembered 1 - 3 cards given that the shopper reads the news 0 times a week? simplify any fractions.

Answer

Explanation:

Step1: Identify relevant values

The number of shoppers who read news 0 times a week and remembered 1 - 3 cards is 7. The total number of shoppers who read news 0 times a week is (7 + 2=9).

Step2: Calculate conditional - probability

The formula for conditional probability (P(A|B)=\frac{P(A\cap B)}{P(B)}). In terms of frequencies, if (A) is the event of remembering 1 - 3 cards and (B) is the event of reading news 0 times a week, then (P(A|B)=\frac{n(A\cap B)}{n(B)}). Here, (n(A\cap B) = 7) and (n(B)=9). So the probability is (\frac{7}{9}).

Answer:

(\frac{7}{9})