4. ricardo randomly chooses a shape from the set of unshaded shapes, and then randomly selects a shape from…

4. ricardo randomly chooses a shape from the set of unshaded shapes, and then randomly selects a shape from the set of shaded shapes. what is the probability that he will choose an unshaded cube, followed by a shaded cube?

4. ricardo randomly chooses a shape from the set of unshaded shapes, and then randomly selects a shape from the set of shaded shapes. what is the probability that he will choose an unshaded cube, followed by a shaded cube?

Answer

Explanation:

Step1: Count unshaded shapes

There are 8 unshaded shapes, and 3 of them are unshaded cubes. So the probability of choosing an unshaded cube first is $\frac{3}{8}$.

Step2: Count shaded shapes

There are 7 shaded shapes, and 2 of them are shaded cubes. So the probability of choosing a shaded cube second is $\frac{2}{7}$.

Step3: Use multiplication rule

The probability of both events happening is the product of their individual probabilities. So $P=\frac{3}{8}\times\frac{2}{7}=\frac{6}{56}=\frac{3}{28}$.

Answer:

$\frac{3}{28}$