sam made a number cube so that the probability of tossing a 4 is $\frac{1}{3}$. which cube pattern could sam…

Explanation:

Step1: Recall probability formula

The probability of an event $P(E)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. For a number - cube, the total number of outcomes is 6.

Step2: Calculate number of favorable outcomes

We know that $P(\text{rolling a }4)=\frac{1}{3}$, and $P(E)=\frac{n}{6}$ (where $n$ is the number of 4s on the cube). Setting $\frac{n}{6}=\frac{1}{3}$, we can solve for $n$ by cross - multiplying: $3n = 6$, so $n = 2$.

Step3: Check each option

We need to find the cube pattern with 2 number 4s.

• Option A has 2 number 4s.
• Option B has 1 number 4.
• Option C has 3 number 4s.
• Option D has 1 number 4.

Answer:

A. 2, 4, 3, 4, 3, 6