in a school, 10% of the students have green eyes. find the experimental probability that in a group of 4…

in a school, 10% of the students have green eyes. find the experimental probability that in a group of 4 students, at least one of them has green eyes. the problem has been simulated by generating random numbers. the digits 0 - 9 were used. let the number \9\ represent the 10% of students with green eyes. a sample of 20 random numbers is shown.\n7918 7910 2546 1390 6075\n1230 2386 0793 7359 3048\n2816 6147 5978 5621 9732\n9436 3806 5971 6173 1430\nexperimental probability = ?%

in a school, 10% of the students have green eyes. find the experimental probability that in a group of 4 students, at least one of them has green eyes. the problem has been simulated by generating random numbers. the digits 0 - 9 were used. let the number \9\ represent the 10% of students with green eyes. a sample of 20 random numbers is shown.\n7918 7910 2546 1390 6075\n1230 2386 0793 7359 3048\n2816 6147 5978 5621 9732\n9436 3806 5971 6173 1430\nexperimental probability = ?%

Answer

Explanation:

Step1: Count total groups

There are 20 groups of 4 - digit numbers, so the total number of trials $n = 20$.

Step2: Count groups with '9'

Count the number of groups that contain the digit '9'. The groups that contain '9' are: 7918, 7910, 1390, 0793, 7359, 9732, 9436, 3806, 5971. There are 9 such groups.

Step3: Calculate experimental - probability

The experimental probability $P$ is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. $P=\frac{9}{20}$ To convert this fraction to a percentage, we use the formula $P(\text{percentage})=\frac{9}{20}\times100%$. $P = 45%$

Answer:

45%