a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon…

a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon 6\nwhat is the experimental probability that the next jelly bean scooped from the bin will be a cinnamon jelly bean?\nwrite your answer as a fraction or whole number.\np(cinnamon) =

a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon 6\nwhat is the experimental probability that the next jelly bean scooped from the bin will be a cinnamon jelly bean?\nwrite your answer as a fraction or whole number.\np(cinnamon) =

Answer

Explanation:

Step1: Calculate total number of jelly - beans

$5 + 22+6=33$

Step2: Calculate probability of cinnamon jelly - bean

The number of cinnamon jelly - beans is 6. The probability $P(\text{cinnamon})$ is the number of cinnamon jelly - beans divided by the total number of jelly - beans. So $P(\text{cinnamon})=\frac{6}{33}=\frac{2}{11}$

Answer:

$\frac{2}{11}$