a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon…

a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon 6\nwhat is the experimental probability that the next jelly bean scooped from the bin will be a cinnamon jelly bean?\nsimplify your answer and write it as a fraction or whole number.\np(cinnamon) =

a scoop from a bin of assorted jelly beans contained a mix of flavors.\nroot beer 5\nlicorice 22\ncinnamon 6\nwhat is the experimental probability that the next jelly bean scooped from the bin will be a cinnamon jelly bean?\nsimplify your answer and write it as a fraction or whole number.\np(cinnamon) =

Answer

Explanation:

Step1: Calculate total jelly - beans

$5 + 22+6=33$

Step2: Calculate probability of cinnamon jelly - bean

$P(\text{cinnamon})=\frac{\text{Number of cinnamon jelly - beans}}{\text{Total number of jelly - beans}}=\frac{6}{33}$

Step3: Simplify the fraction

$\frac{6}{33}=\frac{2}{11}$

Answer:

$\frac{2}{11}$