below are the scores for 21 participants. calculate (using excel) both the mean and sd, and enter the larger…

Explanation:

Step1: List all 21 scores

Scores: $8, 1, 2, 4, 5, 2, 6, 2, 1, 2, 4, 1, 1, 2, 3, 3, 3, 4, 1, 2, 2$

Step2: Calculate the mean

Sum of scores: $8+1+2+4+5+2+6+2+1+2+4+1+1+2+3+3+3+4+1+2+2 = 62$ Mean: $\frac{62}{21} \approx 2.952$

Step3: Calculate sample standard deviation

First, find squared deviations from mean for each score, sum them, divide by $n-1=20$, then take square root. Sum of squared deviations: $(8-2.952)^2 + (1-2.952)^2 + (2-2.952)^2 + (4-2.952)^2 + (5-2.952)^2 + (2-2.952)^2 + (6-2.952)^2 + (2-2.952)^2 + (1-2.952)^2 + (2-2.952)^2 + (4-2.952)^2 + (1-2.952)^2 + (1-2.952)^2 + (2-2.952)^2 + (3-2.952)^2 + (3-2.952)^2 + (3-2.952)^2 + (4-2.952)^2 + (1-2.952)^2 + (2-2.952)^2 + (2-2.952)^2$ $=25.48 + 3.81 + 0.91 + 1.10 + 4.19 + 0.91 + 9.30 + 0.91 + 3.81 + 0.91 + 1.10 + 3.81 + 3.81 + 0.91 + 0.002 + 0.002 + 0.002 + 1.10 + 3.81 + 0.91 + 0.91 \approx 78.476$ Sample SD: $\sqrt{\frac{78.476}{20}} \approx \sqrt{3.924} \approx 1.981$

Step4: Compare mean and SD

Mean $\approx 2.952$, SD $\approx 1.981$. $2.952 > 1.981$

Answer:

$2.95$ (or $\frac{62}{21} \approx 2.95$)