the scores of an eighth - grade math test have a normal distribution with a mean $mu = 83$ and a standard…

the scores of an eighth - grade math test have a normal distribution with a mean $mu = 83$ and a standard deviation $sigma=5$. if dins test score was 92, which expression would she write to find the z - score of her test score?\n$z=\frac{92 - 83}{83}$\n$z=\frac{83 - 92}{5}$\n$z=\frac{92 - 83}{5}$\n$z=\frac{5 - 83}{92}$

the scores of an eighth - grade math test have a normal distribution with a mean $mu = 83$ and a standard deviation $sigma=5$. if dins test score was 92, which expression would she write to find the z - score of her test score?\n$z=\frac{92 - 83}{83}$\n$z=\frac{83 - 92}{5}$\n$z=\frac{92 - 83}{5}$\n$z=\frac{5 - 83}{92}$

Answer

Explanation:

Step1: Recall z - score formula

The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $x$ is the data - point, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Identify values

We are given that $\mu = 83$, $\sigma=5$, and $x = 92$.

Step3: Substitute values into formula

Substitute $x = 92$, $\mu = 83$, and $\sigma = 5$ into the z - score formula: $z=\frac{92 - 83}{5}$.

Answer:

C. $z=\frac{92 - 83}{5}$