the scores of two school basketball teams are recorded. team a scored the following points per game: 67, 45…

the scores of two school basketball teams are recorded. team a scored the following points per game: 67, 45, 92, 77, 73, 72, 80, 62, and 44. team b scored the following points per game: 72, 65, 76, 34, 98, 76, 64, 54, and 64. what is the mean of team a? what is the mean of team b?

the scores of two school basketball teams are recorded. team a scored the following points per game: 67, 45, 92, 77, 73, 72, 80, 62, and 44. team b scored the following points per game: 72, 65, 76, 34, 98, 76, 64, 54, and 64. what is the mean of team a? what is the mean of team b?

Answer

Explanation:

Step1: Recall mean formula

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points.

Step2: Calculate mean of Team A

Team A has $n = 9$ data - points: $x_1 = 67,x_2 = 45,x_3 = 92,x_4 = 77,x_5 = 73,x_6 = 72,x_7 = 80,x_8 = 62,x_9 = 44$. $\sum_{i = 1}^{9}x_{i}=67 + 45+92+77+73+72+80+62+44=612$. $\bar{x}_A=\frac{612}{9}=68$.

Step3: Calculate mean of Team B

Team B has $n = 9$ data - points: $x_1 = 72,x_2 = 65,x_3 = 76,x_4 = 34,x_5 = 98,x_6 = 76,x_7 = 64,x_8 = 54,x_9 = 64$. $\sum_{i = 1}^{9}x_{i}=72 + 65+76+34+98+76+64+54+64=603$. $\bar{x}_B=\frac{603}{9}=67$.

Answer:

Mean of Team A: 68 Mean of Team B: 67