section 3.5 homework\ndue sep 12 by 11:59pm points 7 submitting an external tool\nsection 3.5…

Explanation:

Step1: Find the minimum value

The minimum value in the data - set is the smallest number. Looking at the data set (9,11,12,16,19,31,32,33,46,47,75,79,85,86,89,92,93,95,99), the minimum value is (9).

Step2: Calculate the position of Q1

First, find the number of data points (n = 19). The position of (Q1) is given by (i=\frac{1}{4}(n + 1)=\frac{1}{4}(19+1)=5). So, (Q1) is the 5th - ordered value. Counting from the smallest, (Q1 = 19).

Step3: Calculate the position of the median

The position of the median for (n = 19) (an odd - numbered data set) is (i=\frac{n + 1}{2}=\frac{19+1}{2}=10). So, the median is the 10th - ordered value, which is (47).

Step4: Calculate the position of Q3

The position of (Q3) is given by (i=\frac{3}{4}(n + 1)=\frac{3}{4}(19 + 1)=15). So, (Q3) is the 15th - ordered value. Counting from the smallest, (Q3 = 86).

Step5: Find the maximum value

The maximum value in the data set is the largest number. So, the maximum value is (99).

Answer:

(9,19,47,86,99)