section 5.2 homework\nscore: 9/15 answered: 10/15\n× question 10\nscore on last try: 0 of 1 pts. see details…

section 5.2 homework\nscore: 9/15 answered: 10/15\n× question 10\nscore on last try: 0 of 1 pts. see details for more.\n> next question get a similar question you can retry this question\nthe table summarizes results from 984 pedestrian deaths that were caused by au\npedestrian deaths\ndriver intoxicated? pedestrian intoxicated?\nyes no\nyes 60 69\nno 252 603\nif one of the pedestrian deaths is randomly selected, find the probability that the intoxicated or the driver was not intoxicated. please enter a decimal to 4 decimal\nprobability = 0.9390 ×

section 5.2 homework\nscore: 9/15 answered: 10/15\n× question 10\nscore on last try: 0 of 1 pts. see details for more.\n> next question get a similar question you can retry this question\nthe table summarizes results from 984 pedestrian deaths that were caused by au\npedestrian deaths\ndriver intoxicated? pedestrian intoxicated?\nyes no\nyes 60 69\nno 252 603\nif one of the pedestrian deaths is randomly selected, find the probability that the intoxicated or the driver was not intoxicated. please enter a decimal to 4 decimal\nprobability = 0.9390 ×

Answer

Explanation:

Step1: Calculate total number of cases

The total number of pedestrian - deaths is (60 + 69+252 + 603=984).

Step2: Calculate number of favorable cases

Let (A) be the event that the pedestrian was intoxicated and (B) be the event that the driver was not intoxicated. The number of cases where the pedestrian was intoxicated is (60 + 252=312). The number of cases where the driver was not intoxicated is (252+603 = 855). The number of cases where the pedestrian was intoxicated and the driver was not intoxicated is (252). Using the formula (P(A\cup B)=P(A)+P(B)-P(A\cap B)), we have (n(A\cup B)=312 + 855-252=915).

Step3: Calculate the probability

The probability (P=\frac{n(A\cup B)}{n(\text{total})}=\frac{915}{984}\approx0.9390).

Answer:

(0.9390)