section 5.2 homework\nscore: 0/15 answered 0/15\nquestion 1\na bag of m&ms has 4 red, 3 green, 5 blue, and 7…

section 5.2 homework\nscore: 0/15 answered 0/15\nquestion 1\na bag of m&ms has 4 red, 3 green, 5 blue, and 7 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)\na) a yellow?\nb) a blue or green?\nc) a red or blue or yellow?
Answer
Explanation:
Step1: Calculate total number of M&Ms
$4 + 3+5 + 7=19$
Step2: Calculate probability of picking a yellow
The number of yellow M&Ms is 7. Probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{7}{19}\approx 0.3684$
Step3: Calculate probability of picking a blue or green
Number of blue or green M&Ms is $5 + 3=8$. So $P(\text{blue or green})=\frac{8}{19}\approx 0.4211$
Step4: Calculate probability of picking a red or blue or yellow
Number of red or blue or yellow M&Ms is $4+5 + 7 = 16$. So $P(\text{red or blue or yellow})=\frac{16}{19}\approx 0.8421$
Answer:
a) $0.3684$ b) $0.4211$ c) $0.8421$