section 5.2 homework\nscore: 3/15 answered: 3/15\nquestion 4\nfind the indicated probability\ngiven\np(a) =…

section 5.2 homework\nscore: 3/15 answered: 3/15\nquestion 4\nfind the indicated probability\ngiven\np(a) = 0.3\np(b) = 0.4\np(a or b) = 0.7\nfind\np(a and b) =\nare these events disjoint?\nyes\nno

section 5.2 homework\nscore: 3/15 answered: 3/15\nquestion 4\nfind the indicated probability\ngiven\np(a) = 0.3\np(b) = 0.4\np(a or b) = 0.7\nfind\np(a and b) =\nare these events disjoint?\nyes\nno

Answer

Explanation:

Step1: Recall probability formula

Use the formula $P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$.

Step2: Rearrange formula to solve for $P(A\ and\ B)$

$P(A\ and\ B)=P(A)+P(B)-P(A\ or\ B)$.

Step3: Substitute given values

$P(A\ and\ B)=0.3 + 0.4-0.7$.

Step4: Calculate result

$P(A\ and\ B)=0$.

Step5: Determine if events are disjoint

Disjoint events have $P(A\ and\ B) = 0$. Since $P(A\ and\ B)=0$, the events are disjoint.

Answer:

$P(A\ and\ B)=0$ Yes