section 5.2 homework\nscore: 4/15 answered: 4/15\nquestion 5\nfind the indicated probability\ngiven\np(a) =…

section 5.2 homework\nscore: 4/15 answered: 4/15\nquestion 5\nfind the indicated probability\ngiven\np(a) = 0.5\np(a or b) = 0.7\np(a and b) = 0.2\nfind\np(b) =\nare these events disjoint?\nyes\nno

section 5.2 homework\nscore: 4/15 answered: 4/15\nquestion 5\nfind the indicated probability\ngiven\np(a) = 0.5\np(a or b) = 0.7\np(a and b) = 0.2\nfind\np(b) =\nare these events disjoint?\nyes\nno

Answer

Explanation:

Step1: Recall the formula for P(A or B)

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Step2: Rearrange the formula to solve for P(B)

$P(B)=P(A\cup B)+P(A\cap B)-P(A)$

Step3: Substitute the given values

$P(B)=0.7 + 0.2-0.5$ $P(B)=0.4$

Step4: Determine if events are disjoint

Disjoint events have $P(A\cap B) = 0$. Since $P(A\cap B)=0.2\neq0$, the events are not disjoint.

Answer:

$P(B)=0.4$ No