section 5.2 homework\nscore: 2/15 answered: 7/15\nquestion 3\nfind the indicated probability\ngiven\np(a)=0.4…

section 5.2 homework\nscore: 2/15 answered: 7/15\nquestion 3\nfind the indicated probability\ngiven\np(a)=0.43\np(b)=0.35\np(a or b)=0.65\nfind\np(a and b)\nare a and b mutually exclusive?\n1. yes\n2. no

section 5.2 homework\nscore: 2/15 answered: 7/15\nquestion 3\nfind the indicated probability\ngiven\np(a)=0.43\np(b)=0.35\np(a or b)=0.65\nfind\np(a and b)\nare a and b mutually exclusive?\n1. yes\n2. no

Answer

Explanation:

Step1: Recall the addition - rule formula

The addition - rule for probability is (P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)).

Step2: Rearrange the formula to solve for (P(A\ and\ B))

We can rewrite the formula as (P(A\ and\ B)=P(A)+P(B)-P(A\ or\ B)).

Step3: Substitute the given values

Given (P(A) = 0.43), (P(B)=0.35), and (P(A\ or\ B)=0.65). Substitute these values into the formula: (P(A\ and\ B)=0.43 + 0.35-0.65).

Step4: Calculate the result

(P(A\ and\ B)=0.43+0.35 - 0.65=0.13).

Answer:

(0.13)