section 5.1 homework\nscore: 7/17 answered: 7/17\nquestion 8\na bag of m&ms has 5 red, 6 green, 2 blue, and…

section 5.1 homework\nscore: 7/17 answered: 7/17\nquestion 8\na bag of m&ms has 5 red, 6 green, 2 blue, and 4 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)\na) a yellow?\nb) a blue or green?\nc) an orange?
Answer
Explanation:
Step1: Calculate total number of marbles
$5 + 6+2 + 4=17$
Step2: Calculate probability of picking a yellow marble
The number of yellow marbles is 4. Probability formula is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{4}{17}\approx0.2353$
Step3: Calculate probability of picking a blue or green marble
Number of blue marbles is 2 and green is 6. So number of favorable outcomes for blue or green is $2 + 6=8$. Then $P(\text{blue or green})=\frac{8}{17}\approx0.4706$
Step4: Calculate probability of picking an orange marble
There are 0 orange marbles. So $P(\text{orange})=\frac{0}{17}=0$
Answer:
a) $0.2353$ b) $0.4706$ c) $0$