section 6.1 homework\nscore: 5.67/21 answered: 6/21\nquestion 9\n\n|x|p(x)|\n|0|0.2|\n|1|0.05|\n|2|0.1|\n|3|0…

Explanation:

Step1: Recall mean formula

The mean $\mu$ of a probability - distribution is given by $\mu=\sum_{i}x_{i}P(x_{i})$.

Step2: Calculate the product for each pair

For $x = 0$ and $P(0)=0.2$, the product is $0\times0.2 = 0$. For $x = 1$ and $P(1)=0.05$, the product is $1\times0.05=0.05$. For $x = 2$ and $P(2)=0.1$, the product is $2\times0.1 = 0.2$. For $x = 3$ and $P(3)=0.65$, the product is $3\times0.65 = 1.95$.

Step3: Sum up the products

$\mu=0 + 0.05+0.2 + 1.95=2.2$.

Answer:

$2.2$