select the correct answer from each drop - down menu. carlos is analyzing the results of an experiment on…

select the correct answer from each drop - down menu. carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain after feeding each group a different type of food for one month. the difference in the mean weight gain is 0.6 grams. the standard deviation of the difference in sample means is 0.305. the 68% confidence interval for the population mean difference is ±. the 95% confidence interval for the population mean difference is ±.

select the correct answer from each drop - down menu. carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain after feeding each group a different type of food for one month. the difference in the mean weight gain is 0.6 grams. the standard deviation of the difference in sample means is 0.305. the 68% confidence interval for the population mean difference is ±. the 95% confidence interval for the population mean difference is ±.

Answer

Explanation:

Step1: Recall confidence - interval rules

For a normal distribution, about 68% of the data lies within 1 standard - deviation of the mean, and about 95% of the data lies within 2 standard - deviations of the mean.

Step2: Calculate 68% confidence interval

The 68% confidence interval for the population mean difference is $\pm$ the standard deviation of the difference in sample means. Given the standard deviation of the difference in sample means $s = 0.305$, the 68% confidence interval is $\pm0.305$.

Step3: Calculate 95% confidence interval

The 95% confidence interval for the population mean difference is $\pm2s$. Since $s = 0.305$, then $2s=2\times0.305 = 0.61\approx0.600$.

Answer:

The 68% confidence interval for the population mean difference is $\pm0.305$. The 95% confidence interval for the population mean difference is $\pm0.600$.