select the correct answer from the drop - down menu. of all the sunny club members in a particular city, 25%…

select the correct answer from the drop - down menu. of all the sunny club members in a particular city, 25% prefer swimming on weekends and 75% prefer swimming on weekdays. it is found that 10% of the members in that city prefer swimming on weekends and are female, while 55% of the members in that city prefer swimming on weekdays and are female. the probability that a club member picked randomly is female, given that the person prefers swimming on weekends, is
Answer
Answer:
0.40
Explanation:
Step1: Recall conditional - probability formula
$P(A|B)=\frac{P(A\cap B)}{P(B)}$ Let $A$ be the event that a member is female and $B$ be the event that a member prefers swimming on weekends.
Step2: Identify given probabilities
We know that $P(B) = 0.25$ (probability of preferring swimming on weekends) and $P(A\cap B)=0.10$ (probability of being female and preferring swimming on weekends).
Step3: Calculate the conditional probability
$P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0.10}{0.25}=\frac{10}{25}=0.40$