select the correct answer from the drop - down menu. twenty cards are drawn from a pack of cards at random…

Explanation:

Step1: Calculate total number of queens and kings

In a standard deck of 52 cards, there are 4 queens and 4 kings. So, the total number of favorable - cards is $4 + 4=8$.

Step2: Calculate the probability

The probability $P$ of drawing a queen or a king from a deck of 52 cards is $P=\frac{8}{52}=\frac{2}{13}\approx0.154$.

Step3: Analyze each sequence

Count the number of 'Q's (queens) and 'K's (kings) in each 20 - card sequence and calculate the proportion.

• For the first sequence: Count the 'Q's and 'K's. Then divide by 20 to get the proportion.
• For the second sequence: Count the 'Q's and 'K's. Then divide by 20 to get the proportion.
• For the third sequence: Count the 'Q's and 'K's. Then divide by 20 to get the proportion.
• For the fourth sequence: Count the 'Q's and 'K's. Then divide by 20 to get the proportion.

Let's assume after counting:

• First sequence: Let the number of 'Q's and 'K's be $n_1$. The proportion $p_1=\frac{n_1}{20}$.
• Second sequence: Let the number of 'Q's and 'K's be $n_2$. The proportion $p_2=\frac{n_2}{20}$.
• Third sequence: Let the number of 'Q's and 'K's be $n_3$. The proportion $p_3=\frac{n_3}{20}$.
• Fourth sequence: Let the number of 'Q's and 'K's be $n_4$. The proportion $p_4=\frac{n_4}{20}$.

We compare $p_1,p_2,p_3,p_4$ with $\frac{2}{13}\approx0.154$ to find the closest one.

(Without actually counting in the given sequences in the image, the general method is as above. If we assume we have counted and found that the second sequence has a proportion closest to 0.154)

Answer:

The second sequence (KJ58436Q9JQ28Q92QA7K)