select the correct answer.\na florist gathered data about the weekly number of flower deliveries he made to…

select the correct answer.\na florist gathered data about the weekly number of flower deliveries he made to homes and to businesses for several weeks. he used a graphing tool to organize the data in a scatter - plot, with x representing the number of home deliveries and y representing the number of deliveries to businesses. then he used the graphing tool to find the equation of the line of best fit.\ny = 0.555x + 1.629\nbased on the line of best fit, approximately how many deliveries are predicted to be made to homes during a week with 50 deliveries to businesses?\na. 29\nb. 81\nc. 87\nd. 93

select the correct answer.\na florist gathered data about the weekly number of flower deliveries he made to homes and to businesses for several weeks. he used a graphing tool to organize the data in a scatter - plot, with x representing the number of home deliveries and y representing the number of deliveries to businesses. then he used the graphing tool to find the equation of the line of best fit.\ny = 0.555x + 1.629\nbased on the line of best fit, approximately how many deliveries are predicted to be made to homes during a week with 50 deliveries to businesses?\na. 29\nb. 81\nc. 87\nd. 93

Answer

Explanation:

Step1: Identify the variables

We know $y = 0.555x+1.629$, where $y$ is the number of business - deliveries and $x$ is the number of home - deliveries. We are given $y = 50$ and need to solve for $x$.

Step2: Substitute $y$ into the equation

Substitute $y = 50$ into $y=0.555x + 1.629$. We get $50=0.555x+1.629$.

Step3: Isolate $x$

First, subtract 1.629 from both sides: $50 - 1.629=0.555x$, so $48.371 = 0.555x$. Then, divide both sides by 0.555: $x=\frac{48.371}{0.555}\approx87.16$.

Answer:

C. 87